Calculation of the number of bricks per wall calculator. Online calculation of brickwork by wall area Calculation of the cubature of masonry

The main types of bricks and laying methods

Calculation of the required number of bricks

The main types of bricks and laying methods

Calculation of the required number of bricks

Using online calculators to calculate

General information on the results of calculations

Features of brick consumption on the wall

brick calculator

The principle of determining the consumption of bricks based on the volume of walls

An example of calculating the required number of bricks per unit area

Types and sizes of bricks

Masonry methods

Method of calculation

How to calculate masonry walls with a calculator?

What data will you receive when filling out the form of an online calculator for the number of bricks in a masonry?

masonry calculator

How to calculate the amount of masonry mortar?

Calculation of the amount of brick and mortar for brickwork independently

Getting to the calculation of the number of bricks

How many bricks do you need for a house

We make a competent calculation of the number of bricks for a box at home, excluding doors and windows

Calculation of the number of bricks, taking into account architectural features

Calculation of the number of facing bricks per wall masonry

Calculation of the number of bricks per wall - table!

Algorithm for calculating the amount of facing bricks for building a house

Calculation of the required amount of bricks for building a house using an example

09.11.2019

building brick is one of the most popular building materials in our country in the construction of residential buildings and other buildings for various purposes. Before starting the construction of any brick building, it is necessary to purchase the required amount of bricks, for which a preliminary calculation must be made. Properly carried out calculations will allow you to avoid unnecessary costs for the purchase of unnecessary building materials and avoid problems with their shortage during construction.

Before you start making calculations, you need to determine:

type of brick used;
brick laying method, depending on the desired thickness of the walls of the house;
total area walls of the house (external and internal);
the total area of all window and door openings in all walls of the house.

At the beginning of work, it is necessary to produce.

The standard brick, produced today by various manufacturers, has the same dimensions in length and width (25x12cm) and differs in thickness by:

Single (0.65cm).
One and a half (0.88 cm).
Double (1.38cm).

The most aesthetically pleasing look walls, built of single brick. However, the use of one-and-a-half or double-thickness bricks can greatly speed up and simplify the construction process. At the same time, the consumption of the mortar used for masonry is also significantly saved.

The thickness of the walls of the house depends on the methods of laying bricks. They may be:

in half a brick (wall thickness 12cm);
in 1 brick (wall thickness 25cm);
in 1.5 bricks (wall thickness 38cm);
in 2 bricks (wall thickness 51cm);
in 2.5 bricks (wall thickness 64cm);

In the conditions of the Russian climate, the wall thickness of 2 or 2.5 bricks is considered the most optimal.

The calculation of the number of bricks can be carried out in two main ways:

Without taking into account the thickness of the mortar joint.
Taking into account the thickness of the seam, which is usually from 5 to 10 mm.

It should be borne in mind that when using the first method, an excess of building material by 25-30% can be obtained. The second method is more economical, but at the same time, 10-15% must be added to the calculated value in order to take into account the possible brick breakage during construction.

For clarity, we will carry out the calculation on a specific example: It is necessary to build a one-story brick house 8 by 10m, wall height 3m and without internal brick walls. There is one opening in the outer walls for front door 1 by 2m and three openings for windows 1.2 by 1.5m. The thickness of the walls is two bricks from a standard single brick with a joint thickness of 5mm.

The first layer is placed on the waterproofing

The calculation procedure for the first method will be as follows:

We determine the perimeter of the outer walls: (8 + 10) * 2 = 36m.
We determine the total area of the walls of the house: 36 * 3 \u003d 108 sq.m.
We determine the total area of door and window openings: (1 * 2) + (1.2 * 1.5) * 3 = 7.4 sq.m.
We calculate the area brickwork walls: 108-7.4 = 100.6 sq.m.
We determine the number of bricks in one square meter, for which we calculate the area of \u200b\u200bthe end of one brick: 0.12 * 0.065 \u003d 0.0078 and divide this value by one: 1 / 0.0078 \u003d 128, after which we multiply by two (because masonry will be 2 bricks). We get 128 * 2 = 256 bricks per 1 sq.m.
We calculate the required number of bricks for building a house, multiplying the total area of \u200b\u200bthe walls, excluding openings, by the number of bricks per 1 sq.m: 100.6 * 56 \u003d 25753.6.

Thus, 25.754 bricks will be needed to build the walls of the house.

When calculating according to the second method, to determine the number of bricks in 1 sq.m, we add 5 mm to the standard brick sizes (joint thickness): (0.12 + 0.005) * (0.065 + 0.005) \u003d 0.00875. Accordingly, the number of bricks in 1 sq.m will be: 1 / 0.00875 * 2 = 229 bricks. Multiplying this number by the total area of the masonry, we get: 229 * 100.6 = 23037.4. Let's add to this value about 1500-2000 bricks per battle and we get the amount of bricks needed to build a house: about 24.500-25.000 bricks.

Layer mineral wool between the load-bearing wall and the cladding layer - helps to reduce the overall thickness of the wall

From the above example, it can be seen that the second calculation method is more economical.

The calculation for a different wall thickness is carried out in a similar way, taking into account the appropriate amendments. If you need calculate the number of foam blocks per house — .

Building brick is one of the most popular building materials in our country for the construction of residential buildings and other buildings for various purposes. Before starting the construction of any brick building, it is necessary to purchase the required amount of bricks, for which a preliminary calculation must be made. Properly carried out calculations will allow you to avoid unnecessary costs for the purchase of unnecessary building materials and avoid problems with their shortage during construction.

Before you start making calculations, you need to determine:

type of brick used;
brick laying method, depending on the desired thickness of the walls of the house;
the total area of the walls of the house (external and internal);
the total area of all window and door openings in all walls of the house.

At the beginning of work, it is necessary to calculate the load on the foundation.

The standard brick, produced today by various manufacturers, has the same dimensions in length and width (25x12cm) and differs in thickness by:

Single (0.65cm).
One and a half (0.88 cm).
Double (1.38cm).

The thickness of the walls of the house depends on the methods of laying bricks. They may be:

in half a brick (wall thickness 12cm);
in 1 brick (wall thickness 25cm);
in 1.5 bricks (wall thickness 38cm);
in 2 bricks (wall thickness 51cm);
in 2.5 bricks (wall thickness 64cm);

In the conditions of the Russian climate, the wall thickness of 2 or 2.5 bricks is considered the most optimal.

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The calculation of the number of bricks can be carried out in two main ways:

Without taking into account the thickness of the mortar joint.
Taking into account the thickness of the seam, which is usually from 5 to 10 mm.

For clarity, we will carry out the calculation on a specific example: It is necessary to build a one-story brick house 8 by 10m, with a wall height of 3m and without internal brick walls. In the outer walls there is one opening for the front door 1 by 2m and three openings for windows 1.2 by 1.5m. The thickness of the walls is two bricks from a standard single brick with a joint thickness of 5mm.

The calculation procedure for the first method will be as follows:

We determine the perimeter of the outer walls: (8 + 10) * 2 = 36m.
We determine the total area of the walls of the house: 36 * 3 \u003d 108 sq.m.
We determine the total area of door and window openings: (1 * 2) + (1.2 * 1.5) * 3 = 7.4 sq.m.
We calculate the area of the brickwork of the walls: 108-7.4 = 100.6 sq.m.
We determine the number of bricks in one square meter, for which we calculate the area of \u200b\u200bthe end of one brick: 0.12 * 0.065 \u003d 0.0078 and divide this value by one: 1 / 0.0078 \u003d 128, after which we multiply by two (because masonry will be 2 bricks). We get 128 * 2 = 256 bricks per 1 sq.m.
We calculate the required number of bricks for building a house, multiplying the total area of \u200b\u200bthe walls, excluding openings, by the number of bricks per 1 sq.m: 100.6 * 56 \u003d 25753.6.

Thus, 25.754 bricks will be needed to build the walls of the house.

From the above example, it can be seen that the second calculation method is more economical.

The calculation for a different wall thickness is carried out in a similar way, taking into account the appropriate amendments. If you need calculate the number of foam blocks per house - see this article.

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If you don't want to do mathematical calculations, then to quickly calculate the required amount of bricks to build a house, you can use the free online calculator.

By entering the parameters of the future home in the appropriate fields, you can instantly get the desired result. In addition to calculating the required number of bricks, many online calculators allow you to simultaneously calculate other useful parameters, for example, the required amount of mortar for masonry walls.

chas-repair.com

The construction of various structures using brickwork requires determining the exact amount of material to perform the work.

To carry out such calculations, special online calculators are used, which are widely represented on the Internet, on sites engaged in the trade in building materials. While doing construction works it is necessary to strictly follow the rules and regulations to ensure the further safe and long-term operation of the objects being built, therefore, the parameters of the brickwork are calculated based on the purpose of the structure and environmental conditions.

In addition, bricks from different manufacturers may vary slightly in size and in their properties, which makes it difficult to quickly select the required amount of materials for construction.

The calculator for calculating bricks allows not only to make a calculation during the construction of ordinary walls, but also to make adjustments to the estimate, according to the type of masonry (from 0.5 to 2.5 bricks with dressing), the size of the object being built, the manufacturer of the brick and the type of mortar used. The calculations take into account the implementation of various openings for installing windows and doors, taking into account their future length and width.

The interface of the calculator is very clear and does not require additional calculations. It is enough to enter the basic geometric parameters of the future building to start the calculations in automatic mode. As a result, the consumer receives accurate data on the required number of bricks in pieces, the volume of brickwork in cubic meters, as well as the mortar consumption during operation.

terramall.ru

Building perimeter

The total length of all walls taken into account in the calculations.

Total masonry area

The area of the outer side of the walls. Corresponds to the area of the required insulation, if such is provided for by the project.

wall thickness

The thickness of the finished wall, taking into account the thickness of the mortar joint. May differ slightly from the final result depending on the type of masonry.

Quantity

The total number of bricks required to build walls according to given parameters

Total weight of material

Weight of bricks excluding mortar and masonry mesh. As well as the total volume, it is necessary to select a delivery option.

The amount of mortar for the entire masonry

The volume of mortar required to lay all bricks. The volumetric weight of the solution may differ depending on the ratio of components and additives introduced.

Number of flexible links

Necessary for fastening the facing layer to the main load-bearing walls. The length of flexible connections depends on the total thickness of the wall, taking into account the insulation.

Number of rows in masonry, including seams

Depends on the height of the walls, the dimensions of the material used and the thickness of the masonry mortar. Gables not included.

Number of masonry mesh

The required amount of masonry mesh in meters. It is used to reinforce masonry, increasing the solidity and overall strength of the structure. Pay attention to the number of reinforced rows, by default, the reinforcement of every third row is indicated.

Approximate weight of finished walls

The weight of the finished walls, including all bricks, mortar and masonry mesh, but excluding the weight of insulation and cladding.

Load without taking into account the weight of the roof and floors. This parameter is necessary to select the strength characteristics of the foundation.

To calculate the material for partitions, you need to start a new calculation and specify the length of only all partitions, the thickness of the walls to the brick floor, as well as other necessary parameters.

www.elitpenobeton.ru

When we are talking about the construction of bricks, it is necessary to take into account not only the size of the blocks themselves, as well as the total area and thickness of the walls being built, but also the features of the masonry. The following parameters play a role:

masonry width (from 0.5 to 2.5 bricks);
the thickness of the mortar joint between the blocks (from 0.5 mm);
the number and location of door and window openings in the room.

It is worth taking into account the fact that even when purchasing bricks of a strictly “reference” size of 250x120x65 mm, one cannot be sure that the mortar joint between all blocks will be the same. Firstly, in each batch of building materials there may be a marriage. Secondly, some bricks may be damaged during transportation. One way or another, the difference in size will have to be compensated for by the thickness of the mortar joint. As a result, the pre-calculated building material will be significantly different from what will go in practice.

Such a picture can be avoided, firstly, by taking into account the percentage of possible brick rejects in advance (5-8%; in some online calculators, this parameter is enabled by default). Secondly, all the calculations made with the help of special tools should be duplicated independently for safety net, guided by the algorithm proposed below.

Width of outer and internal walls buildings will be very different. No less noticeable will be the difference between load-bearing walls and simple partitions.
The total area of the door and window openings of the building will not be taken into account in the calculations.

For a better understanding of the principles of this rather complex brick calculation, let's consider the calculations using a specific example. Suppose the object we have planned has the following characteristics:

Internal load-bearing walls are planned to be laid out with a thickness of 1.5 one and a half bricks. Their total length is 22 m.
The number of interior doorways is 4. Their dimensions are 1.25 m x 2.1 m.
Partitions are planned to be laid out with a thickness of 0.5. Their total length is 26 m.
The planned thickness of the outer walls is 2 double.
The number of external doorways is 2 (1.3 x 2.15 m). Window - 7 (1.4 x 1.85 m).

Given these data, in practice, our calculation will look like this:

(2 x 15 x 3) + (2 x 8 x 3) - (7 x 1.4 x 1.85) \u003d 119.86 m² - the area of \u200b\u200bthe outer walls;
(22 x 3) - 4 (1.25 x 2.1) \u003d 55.5 m² - the area of \u200b\u200bthe internal walls;
(26x3) \u003d 78 m² - the area of \u200b\u200bpartitions.

Using reference materials from the Internet, we learn that:

for 1 m² of masonry in 2 doubles, 104 pieces will be required;
for 1 m² of masonry in 1.5 one and a half, 78 pieces will be required;
for 1 m² of masonry in 0.5 standard single bricks, 51 pieces will be required.

Therefore, in total (taking into account the battle and marriage) we need to purchase:

1.08 x (119.86 x 104) = 13463 double pieces;
1.08 x (55.5 x 78) = 4675 one and a half pieces;
1.08 x (78 x 51) = 4296 standard pieces.

That's not like this in a complicated way you can make the necessary calculation of the building material.

domstrousam.ru

To avoid interruption of the construction process due to a shortage of bricks and undesirable spending on the import of purchased building materials, it is better to bring everything at once. Excess material significantly increases the cost of construction. Therefore, if you need to calculate brick for masonry, the online calculator on the construction site is the best modern tool for accurate calculation.

The methodology is based on the determination of the quotient of dividing the total volume of walls (corrected taking into account the deduction of openings for windows and doors) by the volume of one brick. The result is the required amount in pieces for brickwork.

In practice, the problem is solved with the passage of several stages:

determination of the areas of internal walls and partitions, external bearing walls, differing in thickness;
calculation of the areas of window and door openings;
subtracting the size of the openings from the value of the wall area;
calculation of wall volumes by multiplying their corrected area by the thickness;
calculation of a brick for laying external, internal walls and partitions by dividing the obtained wall volumes by the volume of one brick.

The task is complicated by the fact that between the bricks there are seams filled with mortar. Their standard thickness is assumed to be 10 mm, but may be less if the brick has an ideal geometry. A few millimeters of mortar between bricks on a scale of the entire building grows into a rather impressive value, reducing the consumption of bricks.

The simplified calculation is based on the standard dimensions of a single "normal form" brick (1NF) - 250 x 120 x 65 mm (length, width, height). In a cubic meter of masonry of such bricks, exactly 512.82 pieces are placed. Taking into account the seams (10 mm), the difference will be 118 bricks, which for the entire object is a mountain of unnecessary material. Using the calculator online, the purchase of excess building materials will be excluded.

Any batch of bricks initially has a certain percentage of defects. Losses are inevitable during loading, transportation and unloading. This damage increases the calculated amount by 5 - 8%.

Design decision one-story house(ceiling height - 3 m) suggests its rectangular shape with a length of 15 meters and a width of 8 meters. The initial data are also:

length of internal load-bearing walls - 22 m;
partitions length - 26 m;
the number of doors in the outer walls - 2 pcs. (size 1.3 x 2.15 m);
the number of doorways in the inner walls - 4 pcs. (size 1.25 x 2.1 m);
number of windows - 7 (opening size 1.4 x 1.85 m);
type of laying of external walls - in 2 bricks (double);
internal load-bearing walls are designed to be 1.5 bricks (0.38 m);
the thickness of the partitions is 0.5 bricks (0.12 m).

The calculations come down to the definition:

1. Adjusted masonry area of outer walls (without openings):
S \u003d ((2 x 15 x 3) + (2 x 8 x 3) - (7 x 1.4 x 1.85)) \u003d ((90 + 48) - 18.13) \u003d 119.86 m².
2. Areas of internal walls:
V ext.st. \u003d ((22 x 3) - 4 (1.25 x 2.1)) \u003d 55.5 m².
3. Areas of partitions:
V lane \u003d (26x 3) \u003d 78 m².

Using the reference table, the value is determined, how many bricks are in 1 m2 of masonry:

Based on the fact that for a unit area of \u200b\u200bmasonry of 2 bricks (using a double brick), 104 of them are needed, then on the outer walls of the entire building it is necessary:

119.86 x 104 \u003d 12466 pcs. double bricks.

For internal load-bearing walls of 1.5 bricks (one and a half bricks), it is necessary: 78 x 55.5 \u003d 4329 pieces, where 78 is an average value showing how many one and a half bricks are in 1 m2 of masonry with a thickness of 0.38 m.

For partitions of 0.5 bricks of material, you will need: 78 x 51 \u003d 3978 pieces of a single brick.

That. single bricks need to be purchased 3978 x 1.08 = 4296 pieces, one and a half - 4329 x 1.08 = 4675 pieces, and double bricks - 12466 x 1.08 = 13463 pieces - taking into account 8% of waste from battle and marriage.

Using the brick laying calculator, the calculation of its required amount is reduced only to entering the initial data.

remontami.ru

The start of construction is preceded by the calculation and purchase of the required building materials. Properly carried out calculation will prevent the shortage of material during construction or its surplus during construction. in large numbers. Experts recommend purchasing bricks one time to avoid discrepancies in color. To carry out calculations by the amount of material, the following information will be required:

type of bricks used;
laying method, determined on the basis of optimum thickness walls of future housing;
the area of internal partitions and external walls of housing is calculated separately;
dimensions of future windows and doors are taken into account.

Depending on the purpose of the building, in what climatic conditions it will be located, choose the type of brick. According to the material of manufacture, it is classified into the following types:

Adobe products consist of clay and all kinds of fillers.
Most common ceramic material from baked clay.
Sand-lime brick includes sand and lime.
The hyperpressed material includes lime and cement.
Clinker bricks are produced on the basis of special baked clay.
Refractory clay is the source of making fireclay bricks.

Depending on the purpose of use, a brick can be:

Construction (ordinary). Suitable for interior and exterior walls of buildings. Given its unattractive appearance, the likelihood of minor chips, when used outdoors, the walls of future housing are insulated and protected. The external condition of the product does not reduce its strength.
Facing (facade, front) material is characterized by an ideal surface and the absence of defects. Cast facing material ceramic, silicate and hyperpressed products can act. The maximum deviations in dimensions according to GOST are 2, 3 and 4 cm in height, width and length, respectively.

In places high humidity(lowlands or natural areas with a cold climate) ceramic material is best suited due to its low hygroscopicity. In this case, it is better to refuse the option of silicate brick because of its hydrophobic properties. The most suitable operating conditions for silicate material are dry and hot latitudes. Facing brick, in turn, is divided into textured and facade material.

Depending on the filling, the brick is divided into solid and hollow.

The size of all bricks produced by different manufacturers has established standards: the width and length of the product does not change and is 120 and 250 mm, respectively, the thickness is presented in 3 versions:

single - 65 mm;
one and a half - 88 mm;
double - 138 mm.

From an aesthetic point of view, single brick masonry is the most attractive. One and a half and double thickness of the product contributes to the simplification and acceleration of the process of housing construction. In addition to this, there is a significant savings in the consumed solution.

To calculate the amount required material of paramount importance is the method of laying. The main types of solid masonry are represented by the following options:

The thickness of the half-brick wall is 12 cm. This method is used exclusively for internal partitions.
A wall of 1 brick has a thickness of 38 cm.
51 cm - wall standard in 2 bricks;
The wall thickness of 64 cm indicates a laying of 2.5 bricks.

The walls of housing are subjected to loads in three directions: for compression, sideways rotation or displacement. In the first case, the vertical forces from the structures above tend to flatten the wall. In low private houses, these loads are small and the side surfaces have a sufficient margin of safety for compression. Rotating and horizontal impacts result from ground pressure on the basement wall or increased crosswinds. Such loads tend to move the wall section from its place. Housing with thin walls at risk of cracking or even breaking. To ensure a margin of resistance to displacement forces, an increased thickness of the outer side surfaces is included in the design calculation. Given the climatic features Russian regions, the most acceptable is the laying of 2 or 2.5 bricks.

There are two main options for determining the amount of bricks needed for housing construction:

the thickness of the connecting seams is not taken into account;
taking into account the size of the mortar joint, which ranges from 5 to 10 mm.

The calculation according to the first option usually leads to the formation of excess building materials. The second option is more economical, but 10-15% is added to the result in case possible losses during construction.

We will give the calculation procedure using an example with specific data:

it is planned to build a 1-storey brick house 9x10 m, 3 m high;
laying of external walls in 2 bricks, 1 door 1x2 m and 4 windows 1.2x1.5 m are provided;
a single brick is used, the thickness of the mortar joint of the outer side surfaces and partitions is 7 mm;
internal partitions in half-brick, two 10 m long, one - 9 m;
partitions have 5 doors 1x2 m;

First of all, the amount of material for the outer side structures is determined. The calculation algorithm includes the following steps:

Perimeter of load-bearing walls: (9+10)x2=38 m.
The total area of the outer side structures: 38x3=114 m 2 .
The total area of window openings and doors: 4x (1.2x1.5) + 1x2 \u003d 9.2 m 2.
Net masonry area of the outer walls: 114-9.2 = 104.8 m 2.
To calculate the amount of building material in 1 m 2, we determine the area of \u200b\u200bthe end part of one product: 0.12x0.065 \u003d 0.0078 m 2, respectively, in 1 m 2 there will be 1 / 0.0078 \u003d 128 products. Taking into account the laying method, the value doubles and it turns out 256 pieces per 1 m 2.
For the construction of load-bearing side surfaces, you will need: 104.8x256 \u003d 26829 copies of the product.

Similarly, the amount of material for internal partitions is calculated:

Total area of internal structures: 2x(10x3)+9x3=87 m2.
Square internal doors: 5x1x2 \u003d 10 m 2.
Net area of partitions: 87-10=77 m2.
Area of 1 product (spoon part): 0.25x0.065 \u003d 0.01625 m 2.
Quantity in 1 m 2: 1 / 0.01625 \u003d 61.5 pieces.
For all partitions: 77x33.3 = 4736 pieces.

Determine the total amount of material for the outer and inner walls: 26829+4736=31565 pieces.

In the second option, when calculating the area of a brick, we add the value of the mortar joint:

For external walls: (0.12+0.007)x(0.065+0.007)=0.00914
Quantity in 1 m 2: 1 / 0.00914 \u003d 109.4 pieces, taking into account laying in 2 bricks: 109.4x2 \u003d 219 pieces.
Total quantity for exterior walls: 104.8x219=22951 pieces.
The area of the spoon part of the brick for internal partitions: (0.25 + 0.007) x (0.065 + 0.007) \u003d 0.0185 m 2.
Quantity in 1 m 2: 1 / 0.0185 = 54 pieces.
Total quantity for internal partitions: 77х54=4158 pieces.
Total for exterior and interior walls: 22951+4158=27109 pieces.

The results of calculating the total area of the outer side surfaces allow you to purchase insulation, if it is provided for by the project. If you do not want to make calculations on the number of required bricks on your own, on help will come online calculator.

Before building a brick house, it will be correct to calculate the amount of bricks in the masonry, and in this case, an online calculator will be a great helper, which will calculate the amount of brick and mortar for the future construction or cladding of the structure, as well as other related materials.

Thanks to the masonry calculator, you can calculate the amount of masonry mortar, flexible connections, and the result will be as accurate as possible, depending on the individual parameters entered by the user in the table.

Brick is the most popular and widespread building material, serves long time and pleases neat appearance. To date, there are several types of bricks for the construction of buildings:

brick made of clay and other fillers, called adobe;
ceramic, the most used, from fired clay;
silicate, made from sand and lime;
with the addition of cement - hyperpressed;
clinker, from a special composition;
refractory.

Such materials are used both for laying a house and for building additional finishing in the future, the creation of a facade, interior structures. Fireclay bricks can withstand high temperatures as well as various heating and cooling cycles without losing strength.

Bricks can be hollow, porous, the most common standard size of this product is 250 × 120 × 65 mm, with preliminary calculations of brick laying consumption, the dimensions of the brick increase by 10 mm of each parameter.

The total length of all walls of the structure along the perimeter of the building.
The total area of the masonry of the outer side of the walls.
The wall thickness will be taken into account based on the thickness of the finished wall and the size of the mortar joint.
The total number of bricks and the total weight of the material.
The amount of mortar for the entire masonry will depend on the ratio of the components and the additives introduced.
And the length of flexible connections will be determined by the total thickness of the wall, taking into account the amount of insulation base.
The amount of masonry mesh will improve the overall strength of the structure.
The approximate weight of the finished walls will be calculated without taking into account the weight of insulation materials and cladding.

To make the calculation of a brick for masonry with a calculator - online, you need to enter the required parameters in the prepared table and click on the "calculate" button. Within a few seconds, the program will give the most accurate result. The percentage of error can range from 3 to 7%.

To make a mortar for masonry, you need to mix sand and cement to create a plastic mixture, usually this ratio of materials is equal to a third of the sand and one cement.

But the final consumption will be determined by the special requirements according to the laying material and the brand of raw materials used. Often, additional additives (clinker, marble, crushed stone, synthetic substances) are added to the finished mixture in order to increase the setting speed of the masonry and increase the strength of the material.

The calculation of the amount of mortar for brickwork can be done using an online calculator, which in a matter of seconds most accurately determines the amount of mortar per brickwork.

Types of brick joints

The consumption of the solution depends on the type of the selected type of seams.

Such a program will allow you to make calculations regarding the total volume of the cement mixture. The reliability of the data obtained will be determined by the accuracy of specifying the dimensions of the wall and seams.

In the presence of concrete wall belts, a calculation is provided from the height of general measurements. The construction calculator for the consumption of mortar per 1 m 2 of brickwork makes it possible to quickly and conveniently calculate the desired parameters.

Types and sizes of bricks for masonry

Such data will allow you to navigate the cost of masonry, as well as calculate the required amount for the construction of the building. Depending on the additional additives, the rigidity, strength, mobility and setting of concrete will depend

The mortar consumption calculator for brickwork will help you avoid unnecessary material costs if you correctly calculate the consumption of other works, for example, pouring a foundation, screeding walls, etc.

There are other, more troublesome options for calculating the amount of brick in 1 m 2 of masonry and the required mortar. How to calculate the material per 1 m 3?

To build one cubic meter of wall, you need to take about 400 pieces. bricks with a margin of 10 pcs., Norm consumption - 0.23 m 3 per 1 cubic meter, if you use a hollow brick, then the mortar consumption will increase several times to fill all voids and depressions.

Without an online brickwork calculator, you need to manually produce a lot of calculated data, you need to know the geometric dimensions of the intended brickwork, taking into account the type of brick and its thickness.

It is best to entrust such work to specialists, so as not to follow false data and not lose material investments. If the construction of walls 5 m long and 3 m high is required, then the area of \u200b\u200bsuch a wall will be 15 m 2, 51 pieces of bricks will be required for such masonry.

There are many tables and prepared materials where you can get acquainted with the data on the size of the brick, the type of work and the amount of mortar used. Based on these figures, you can get the desired result.

And when using the masonry calculator, the calculation work is performed much faster and most accurately, with a maximum number of deviations of up to 7%. Build and count quickly, correctly and enjoy the result!

Masonry mortar calculation table for walls of different thicknesses (per 1 m3)

Do you have big plans for building a house? So, what is next? To begin with, you have to purchase a huge amount of building materials. But how to do this so as not to buy too much, because large construction is already a costly business? The decision has been made, the new dwelling will be built of strong and reliable bricks. Here the question reasonably arises of how to calculate the number of bricks per house?

First of all, let's decide what kind of structure you will build, one- or two-story, and which one will be. Usually, for the climate of central Russia, the outer walls are built in two or two and a half bricks, which are five hundred and ten and six hundred and forty millimeters, respectively. Next, we estimate the approximate area of \u200b\u200bthe future house: its length, width, and also necessarily height. Calculations will be made separately for each wall. So, multiplying the length of one of them by the height, we get the total wall area along its perimeter. Then, from the resulting number, it is necessary to subtract the area of \u200b\u200bthe window or doorways. By adding, we determine the total area of \u200b\u200bthe walls of the house.

Not only the correct calculation of the parameters of the future structure, but also the choice of the material itself will help you calculate the number of bricks per house. Bricks can be single, double and one and a half. To complete construction faster, most often choose the type

The next important indicator, without which it is impossible to make the correct calculation of the required brick, is the thickness of the masonry and mortar joint. We choose a seam size of ten millimeters. We will take the expense for one square meter.

▪ Determine the perimeter of the house with a length of ten meters and a width of eight. (6 + 6+ 8 + 8 = 28 m).

▪ We designate the area of the outer walls of the whole house. For example, its height is three and a half meters, then the total area of \u200b\u200ball the walls will be 28 × 3.5; i.e. 98 m.

▪ Calculate wall thickness. Let's say the design thickness is 510 millimeters. It follows from this that one and a half bricks (380 millimeters) will be laid from an ordinary one and a half and one more row of half a brick from the front one and a half.

▪ Considering the thickness of the mortar joints, we obtain the following calculation:

◦ ordinary - 98 × 117 = 11,466 units;

◦ Front one-and-a-half bricks - 98 × 9 = 3822 pieces.

Another example of how to calculate the number of bricks per house is an online calculator on the Internet. You will see an approximate table in which you only need to enter the size, length of the outer walls, their area. Do not forget to decide on the thickness of the masonry: two, one and a half or two and a half bricks.

Making a calculation

It will take 38154 pieces.

How to calculate how many bricks are needed per house, we learned from these examples. But always when buying a building material, you need to remember that in this way its exact amount is calculated. In reality, it is necessary to purchase seven to ten percent more, taking into account possible defective material or a fight when laying walls.

Good luck in your endeavor!

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1. Calculate the perimeter P (m) of the building, for this we add two lengths and two widths of the building.

2. Calculate the total area Stot (m2) of the outer walls, for this we multiply the calculated perimeter by the height of the building H (m).

3. Calculate the area of window and door openings Sopen (m2).

4. Calculate the area of the walls for brick cladding S (m2), for this, from the result of the total area of the outer walls Stot (m2), subtract the area of the window and door openings Sopen (m2)

S = Stotal (m2) - Sopening (m2).

5. Calculation of the consumption of facing bricks per square meter of masonry:

a) for laying half a brick, we take its length and multiply by the height of the brick and get it

square brick (m2), for a standard brick 250x120x65 mm, where:

250 - brick length, mm (0.25 m),

120 - brick width, mm (0.12 m),

65 - brick height, mm (0.065 m),

Skirp=250?65=16250 mm2 (0.01625 m2);

b) in order to determine the number of bricks in one square meter, it is necessary to divide the unit by the area of one brick 1: 0.0162 \u003d 61.538 (pcs),

we round up and get that 61 bricks per square meter are required, excluding the seam.

c) but masonry facing brick is made for mortar, and then it is also necessary to take into account the thickness of the seams, for this we will add one side and one spoon seam to the size of the brick.

1-vertical seam, 2-horizontal seam.

As an example, take a seam equal to 10mm.

We get:

brick length 250+10=260 mm (0.26 m),

brick height 65+10=75 mm (0.075 m),

brick area, taking into account the seams Skirp. seam \u003d 0.26? 0.075 \u003d 0.0195 (m2),

therefore, one square meter requires 1: 0.0195 = 51.28 (pcs),

we round up and get that 51 pieces of brick per square meter are required, taking into account the seam.

6. The total number of facing bricks is calculated: S? quantity per 1m2.

This calculation is the theoretical number of bricks, but do not forget to take into account 5% of the battle!!!

By the same analogy, you can calculate the required number of bricks per square meter when laying in one brick, one and a half, two, etc.

Type of brick

Wall thickness in bricks

(250×120×65mm)

Brick, pcs.

(250×120×65mm)

Solution, m 3

Modulated

(250×120×88mm)

Brick, pcs.

Modulated

(250×120×88mm)

Solution, m 3

Suppose we need to calculate how much brick we need for facing two-story house 10.5 × 9.7 m in size, 6 m high, windows 1.5 × 2 m in size in the amount of 10 pcs. and a doorway of 1.3 × 2 m. We will produce cladding in half a brick and choose a seam of 9 mm.

When solving a problem, it is necessary to determine how many facing brick units will be required for finishing the exterior surfaces of the house.

1. Calculate the perimeter of the building: Р=10.5+9.7+10.5+9.7=40.4 m.

2. We calculate the total area of the outer walls: Stot = 40.4? 6 = 242.4 m2.

3. Calculate the area of windows and doors: Sopening = Swindow + Sdoor,

the area of one window Socon \u003d 1.5? 2 \u003d 3 m2,

then the area of all ten windows will be Sokon \u003d 3 m2? 10 \u003d 30 m2,

door area Sdoor \u003d 1.3? 2 \u003d 2.6 m2,

Sopening = Swindow + Sdoor = Sopening = 30 + 2.6 = 32.6 m2

4. We calculate the area of \u200b\u200bthe walls for brick cladding:

S \u003d Stotal - Sopening (m2) \u003d 242.4 - 32.6 \u003d 209.8 (m2).

5. Calculate the required number of bricks per square meter, taking into account the seam:

Skype. seam \u003d (250mm + 9mm)? (65mm + 9mm) \u003d 0.259? 0.074 \u003d 0.019166 (m2).

The number of bricks per 1m2 = 1: 0.019166 = 52.175 pieces per 1m2. We accept 52 pieces per 1m2.

6. Calculate the total number of bricks: S? The number of bricks per 1m2.

The total number of facing bricks = 209.8 m2 × 52 pcs per 1m2 = 10909.6 pcs.

Taking into account the battle, we get = 10909.6 pcs + 5% = 11455 pcs.